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4/7x-2/3x=13
We move all terms to the left:
4/7x-2/3x-(13)=0
Domain of the equation: 7x!=0
x!=0/7
x!=0
x∈R
Domain of the equation: 3x!=0We calculate fractions
x!=0/3
x!=0
x∈R
12x/21x^2+(-14x)/21x^2-13=0
We multiply all the terms by the denominator
12x+(-14x)-13*21x^2=0
Wy multiply elements
-273x^2+12x+(-14x)=0
We get rid of parentheses
-273x^2+12x-14x=0
We add all the numbers together, and all the variables
-273x^2-2x=0
a = -273; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·(-273)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*-273}=\frac{0}{-546} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*-273}=\frac{4}{-546} =-2/273 $
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