7/3=(2x+5)/x

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Solution for 7/3=(2x+5)/x equation: 



7/3=(2x+5)/x

We move all terms to the left:

7/3-((2x+5)/x)=0



Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R



We calculate fractions


(-((2x+5)*3)/x*3)+7x/x*3)=0



We calculate terms in parentheses: +(-((2x+5)*3)/x*3), so:

-((2x+5)*3)/x*3

We multiply all the terms by the denominator


-((2x+5)*3)



We calculate terms in parentheses: -((2x+5)*3), so:

(2x+5)*3

We multiply parentheses

6x+15

Back to the equation:

-(6x+15)



We get rid of parentheses

-6x-15

Back to the equation:

+(-6x-15)



We get rid of parentheses

-6x+7x/x*3)-15=0

We multiply all the terms by the denominator


-6x*x*3)-15+7x=0

Wy multiply elements

-18x^3*3=0

We do not support expression: x^3

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