2(3x-1)+(-x)=8+3(-x)+6x

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Solution for 2(3x-1)+(-x)=8+3(-x)+6x equation: 



2(3x-1)+(-x)=8+3(-x)+6x

We move all terms to the left:

2(3x-1)+(-x)-(8+3(-x)+6x)=0

We add all the numbers together, and all the variables

2(3x-1)+(-1x)-(8+3(-1x)+6x)=0

We multiply parentheses

6x+(-1x)-(8+3(-1x)+6x)-2=0

We get rid of parentheses

6x-1x-(8+3(-1x)+6x)-2=0



We calculate terms in parentheses: -(8+3(-1x)+6x), so:

8+3(-1x)+6x

determiningTheFunctionDomain
3(-1x)+6x+8

We add all the numbers together, and all the variables

6x+3(-1x)+8

We multiply parentheses

6x-3x+8

We add all the numbers together, and all the variables

3x+8

Back to the equation:

-(3x+8)



We add all the numbers together, and all the variables

5x-(3x+8)-2=0

We get rid of parentheses

5x-3x-8-2=0

We add all the numbers together, and all the variables

2x-10=0

We move all terms containing x to the left, all other terms to the right

2x=10

x=10/2

x=5

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