7/2(x+12)=5/2(20+x)

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Solution for 7/2(x+12)=5/2(20+x) equation: 



7/2(x+12)=5/2(20+x)

We move all terms to the left:

7/2(x+12)-(5/2(20+x))=0



Domain of the equation: 2(x+12)!=0

x∈R





Domain of the equation: 2(20+x))!=0

x∈R



We add all the numbers together, and all the variables

7/2(x+12)-(5/2(x+20))=0

We calculate fractions


(14xx/(2(x+12)*2(x+20)))+(-10xx/(2(x+12)*2(x+20)))=0



We calculate terms in parentheses: +(14xx/(2(x+12)*2(x+20))), so:

14xx/(2(x+12)*2(x+20))

We multiply all the terms by the denominator


14xx

Back to the equation:

+(14xx)





We calculate terms in parentheses: +(-10xx/(2(x+12)*2(x+20))), so:

-10xx/(2(x+12)*2(x+20))

We multiply all the terms by the denominator


-10xx

Back to the equation:

+(-10xx)



We get rid of parentheses

14xx-10xx=0

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