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7/10x+24=x
We move all terms to the left:
7/10x+24-(x)=0
Domain of the equation: 10x!=0We add all the numbers together, and all the variables
x!=0/10
x!=0
x∈R
-1x+7/10x+24=0
We multiply all the terms by the denominator
-1x*10x+24*10x+7=0
Wy multiply elements
-10x^2+240x+7=0
a = -10; b = 240; c = +7;
Δ = b2-4ac
Δ = 2402-4·(-10)·7
Δ = 57880
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{57880}=\sqrt{4*14470}=\sqrt{4}*\sqrt{14470}=2\sqrt{14470}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(240)-2\sqrt{14470}}{2*-10}=\frac{-240-2\sqrt{14470}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(240)+2\sqrt{14470}}{2*-10}=\frac{-240+2\sqrt{14470}}{-20} $
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