6x+4(4x-x)=48

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Solution for 6x+4(4x-x)=48 equation: 



6x+4(4x-x)=48

We move all terms to the left:

6x+4(4x-x)-(48)=0

We add all the numbers together, and all the variables

6x+4(+3x)-48=0

We multiply parentheses

6x+12x-48=0

We add all the numbers together, and all the variables

18x-48=0

We move all terms containing x to the left, all other terms to the right

18x=48

x=48/18

x=2+2/3

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