7/(n+8)=3/(n-4)

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Solution for 7/(n+8)=3/(n-4) equation: 



7/(n+8)=3/(n-4)

We move all terms to the left:

7/(n+8)-(3/(n-4))=0



Domain of the equation: (n+8)!=0

We move all terms containing n to the left, all other terms to the right

n!=-8

n∈R





Domain of the equation: (n-4))!=0

n∈R



We calculate fractions


7n/((n+8)*(n-4)))+(-(3*(n+8))/((n+8)*(n-4)))=0



We calculate terms in parentheses: -(3*(n+8))/((n+8)*(n-4))), so:

3*(n+8))/((n+8)*(n-4))

We multiply all the terms by the denominator


3*(n+8))

We multiply parentheses

3n+

We add all the numbers together, and all the variables

3n

Back to the equation:

-(3n)



We add all the numbers together, and all the variables

-3n+7n/((n+8)*(n-4)))+(=0

We multiply all the terms by the denominator


-3n*((n+8)*(n-4)))+(+7n=0

We add all the numbers together, and all the variables

7n-3n*((n+8)*(n-4)))+(=0

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