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5+3q-12=2(q+1)
We move all terms to the left:
5+3q-12-(2(q+1))=0
We add all the numbers together, and all the variables
3q-(2(q+1))-7=0
We calculate terms in parentheses: -(2(q+1)), so:We get rid of parentheses
2(q+1)
We multiply parentheses
2q+2
Back to the equation:
-(2q+2)
3q-2q-2-7=0
We add all the numbers together, and all the variables
q-9=0
We move all terms containing q to the left, all other terms to the right
q=9
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