8x=4(2x/1)

Solution for 8x=4(2x/1) equation:

8x=4(2x/1)

We move all terms to the left:

8x-(4(2x/1))=0

We add all the numbers together, and all the variables

8x-(4(+2x/1))=0

We multiply all the terms by the denominator


8x*1))-(4(+2x=0

We add all the numbers together, and all the variables

2x+8x*1))-(4(=0

Wy multiply elements

8x^2+2x=0

a = 8; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·8·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*8}=\frac{-4}{16}
=-1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*8}=\frac{0}{16}
=0
$