7/(-2m-5)=3/(3-m)

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Solution for 7/(-2m-5)=3/(3-m) equation: 



7/(-2m-5)=3/(3-m)

We move all terms to the left:

7/(-2m-5)-(3/(3-m))=0



Domain of the equation: (-2m-5)!=0

We move all terms containing m to the left, all other terms to the right

-2m!=5

m!=5/-2

m!=-2+1/2

m∈R





Domain of the equation: (3-m))!=0

We move all terms containing m to the left, all other terms to the right

-m)!=-3

m!=-3/1

m!=-3

m∈R



We add all the numbers together, and all the variables

7/(-2m-5)-(3/(-1m+3))=0

We calculate fractions


(-7m)/((-2m-5)*(-1m+3)))+(-(3*(-2m-5))/((-2m-5)*(-1m+3)))=0



We calculate terms in parentheses: -(3*(-2m-5))/((-2m-5)*(-1m+3))), so:

3*(-2m-5))/((-2m-5)*(-1m+3))

We multiply all the terms by the denominator


3*(-2m-5))

We multiply parentheses

-6m+

We add all the numbers together, and all the variables

-6m

Back to the equation:

-(-6m)



We get rid of parentheses

(-7m)/((-2m-5)*(-1m+3)))+(+6m=0

We multiply all the terms by the denominator


(-7m)+6m*((-2m-5)*(-1m+3)))+(=0

We get rid of parentheses

-7m+6m*((-2m-5)*(-1m+3)))+(=0

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