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5x^2+140x-465=0
a = 5; b = 140; c = -465;
Δ = b2-4ac
Δ = 1402-4·5·(-465)
Δ = 28900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{28900}=170$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(140)-170}{2*5}=\frac{-310}{10} =-31 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(140)+170}{2*5}=\frac{30}{10} =3 $
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