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7.17x(x/3)+3(2x/3)=18(6/3)
We move all terms to the left:
7.17x(x/3)+3(2x/3)-(18(6/3))=0
We add all the numbers together, and all the variables
7.17x(+x/3)+3(+2x/3)-(182)=0
We add all the numbers together, and all the variables
7.17x(+x/3)+3(+2x/3)-182=0
We multiply parentheses
7x^2+6x-182=0
a = 7; b = 6; c = -182;
Δ = b2-4ac
Δ = 62-4·7·(-182)
Δ = 5132
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5132}=\sqrt{4*1283}=\sqrt{4}*\sqrt{1283}=2\sqrt{1283}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{1283}}{2*7}=\frac{-6-2\sqrt{1283}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{1283}}{2*7}=\frac{-6+2\sqrt{1283}}{14} $
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