4y=6(y-2)=22

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Solution for 4y=6(y-2)=22 equation: 



4y=6(y-2)=22

We move all terms to the left:

4y-(6(y-2))=0



We calculate terms in parentheses: -(6(y-2)), so:

6(y-2)

We multiply parentheses

6y-12

Back to the equation:

-(6y-12)



We get rid of parentheses

4y-6y+12=0

We add all the numbers together, and all the variables

-2y+12=0

We move all terms containing y to the left, all other terms to the right

-2y=-12

y=-12/-2

y=+6

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