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X=4X-5/2X+1
We move all terms to the left:
X-(4X-5/2X+1)=0
Domain of the equation: 2X+1)!=0We get rid of parentheses
X∈R
X-4X+5/2X-1=0
We multiply all the terms by the denominator
X*2X-4X*2X-1*2X+5=0
Wy multiply elements
2X^2-8X^2-2X+5=0
We add all the numbers together, and all the variables
-6X^2-2X+5=0
a = -6; b = -2; c = +5;
Δ = b2-4ac
Δ = -22-4·(-6)·5
Δ = 124
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{124}=\sqrt{4*31}=\sqrt{4}*\sqrt{31}=2\sqrt{31}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{31}}{2*-6}=\frac{2-2\sqrt{31}}{-12} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{31}}{2*-6}=\frac{2+2\sqrt{31}}{-12} $
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