7-4(x+1)-3=7+2(4+2x)-16

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Solution for 7-4(x+1)-3=7+2(4+2x)-16 equation: 



7-4(x+1)-3=7+2(4+2x)-16

We move all terms to the left:

7-4(x+1)-3-(7+2(4+2x)-16)=0

We add all the numbers together, and all the variables

-4(x+1)-(7+2(2x+4)-16)+7-3=0

We add all the numbers together, and all the variables

-4(x+1)-(7+2(2x+4)-16)+4=0

We multiply parentheses

-4x-(7+2(2x+4)-16)-4+4=0



We calculate terms in parentheses: -(7+2(2x+4)-16), so:

7+2(2x+4)-16

determiningTheFunctionDomain
2(2x+4)+7-16

We add all the numbers together, and all the variables

2(2x+4)-9

We multiply parentheses

4x+8-9

We add all the numbers together, and all the variables

4x-1

Back to the equation:

-(4x-1)



We add all the numbers together, and all the variables

-4x-(4x-1)=0

We get rid of parentheses

-4x-4x+1=0

We add all the numbers together, and all the variables

-8x+1=0

We move all terms containing x to the left, all other terms to the right

-8x=-1

x=-1/-8

x=1/8

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