7-4(x+1)-3=7+2(4+2)-16

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Solution for 7-4(x+1)-3=7+2(4+2)-16 equation: 



7-4(x+1)-3=7+2(4+2)-16

We move all terms to the left:

7-4(x+1)-3-(7+2(4+2)-16)=0

We add all the numbers together, and all the variables

-4(x+1)+7-3-(7+26-16)=0

We add all the numbers together, and all the variables

-4(x+1)-13=0

We multiply parentheses

-4x-4-13=0

We add all the numbers together, and all the variables

-4x-17=0

We move all terms containing x to the left, all other terms to the right

-4x=17

x=17/-4

x=-4+1/4

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