7-4(m-3)-(m+5)=10-3m+4-4(m-6)

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Solution for 7-4(m-3)-(m+5)=10-3m+4-4(m-6) equation: 



7-4(m-3)-(m+5)=10-3m+4-4(m-6)

We move all terms to the left:

7-4(m-3)-(m+5)-(10-3m+4-4(m-6))=0

We multiply parentheses

-4m-(m+5)-(10-3m+4-4(m-6))+12+7=0

We get rid of parentheses

-4m-m-(10-3m+4-4(m-6))-5+12+7=0



We calculate terms in parentheses: -(10-3m+4-4(m-6)), so:

10-3m+4-4(m-6)

determiningTheFunctionDomain
-3m-4(m-6)+10+4

We add all the numbers together, and all the variables

-3m-4(m-6)+14

We multiply parentheses

-3m-4m+24+14

We add all the numbers together, and all the variables

-7m+38

Back to the equation:

-(-7m+38)



We add all the numbers together, and all the variables

-5m-(-7m+38)+14=0

We get rid of parentheses

-5m+7m-38+14=0

We add all the numbers together, and all the variables

2m-24=0

We move all terms containing m to the left, all other terms to the right

2m=24

m=24/2

m=12

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