7-4(4x-5)=1+2(8x-4)

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Solution for 7-4(4x-5)=1+2(8x-4) equation: 



7-4(4x-5)=1+2(8x-4)

We move all terms to the left:

7-4(4x-5)-(1+2(8x-4))=0

We multiply parentheses

-16x-(1+2(8x-4))+20+7=0



We calculate terms in parentheses: -(1+2(8x-4)), so:

1+2(8x-4)

determiningTheFunctionDomain
2(8x-4)+1

We multiply parentheses

16x-8+1

We add all the numbers together, and all the variables

16x-7

Back to the equation:

-(16x-7)



We add all the numbers together, and all the variables

-16x-(16x-7)+27=0

We get rid of parentheses

-16x-16x+7+27=0

We add all the numbers together, and all the variables

-32x+34=0

We move all terms containing x to the left, all other terms to the right

-32x=-34

x=-34/-32

x=1+1/16

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