1/2x+1/3x=-20

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Solution for 1/2x+1/3x=-20 equation:



1/2x+1/3x=-20
We move all terms to the left:
1/2x+1/3x-(-20)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
We add all the numbers together, and all the variables
1/2x+1/3x+20=0
We calculate fractions
3x/6x^2+2x/6x^2+20=0
We multiply all the terms by the denominator
3x+2x+20*6x^2=0
We add all the numbers together, and all the variables
5x+20*6x^2=0
Wy multiply elements
120x^2+5x=0
a = 120; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·120·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*120}=\frac{-10}{240} =-1/24 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*120}=\frac{0}{240} =0 $

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