7-3(3-2x)=4(x-4)+2x+11

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Solution for 7-3(3-2x)=4(x-4)+2x+11 equation: 



7-3(3-2x)=4(x-4)+2x+11

We move all terms to the left:

7-3(3-2x)-(4(x-4)+2x+11)=0

We add all the numbers together, and all the variables

-3(-2x+3)-(4(x-4)+2x+11)+7=0

We multiply parentheses

6x-(4(x-4)+2x+11)-9+7=0



We calculate terms in parentheses: -(4(x-4)+2x+11), so:

4(x-4)+2x+11

We add all the numbers together, and all the variables

2x+4(x-4)+11

We multiply parentheses

2x+4x-16+11

We add all the numbers together, and all the variables

6x-5

Back to the equation:

-(6x-5)



We add all the numbers together, and all the variables

6x-(6x-5)-2=0

We get rid of parentheses

6x-6x+5-2=0

We add all the numbers together, and all the variables

3!=0

There is no solution for this equation

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