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(-3z^2+2z-1)-(-z2+5z+3)=
We move all terms to the left:
(-3z^2+2z-1)-(-z2+5z+3)-()=0
We add all the numbers together, and all the variables
(-3z^2+2z-1)-(-1z^2+5z+3)-()=0
We add all the numbers together, and all the variables
(-3z^2+2z-1)-(-1z^2+5z+3)=0
We get rid of parentheses
-3z^2+1z^2+2z-5z-1-3=0
We add all the numbers together, and all the variables
-2z^2-3z-4=0
a = -2; b = -3; c = -4;
Δ = b2-4ac
Δ = -32-4·(-2)·(-4)
Δ = -23
Delta is less than zero, so there is no solution for the equation
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