7-2(3x+9)-(9x+(4-(3x+1)))=12*(x+1)-2

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Solution for 7-2(3x+9)-(9x+(4-(3x+1)))=12*(x+1)-2 equation: 



7-2(3x+9)-(9x+(4-(3x+1)))=12(x+1)-2

We move all terms to the left:

7-2(3x+9)-(9x+(4-(3x+1)))-(12(x+1)-2)=0

We multiply parentheses

-6x-(9x+(4-(3x+1)))-(12(x+1)-2)-18+7=0



We calculate terms in parentheses: -(9x+(4-(3x+1))), so:

9x+(4-(3x+1))



We calculate terms in parentheses: +(4-(3x+1)), so:

4-(3x+1)

determiningTheFunctionDomain
-(3x+1)+4

We get rid of parentheses

-3x-1+4

We add all the numbers together, and all the variables

-3x+3

Back to the equation:

+(-3x+3)



We get rid of parentheses

9x-3x+3

We add all the numbers together, and all the variables

6x+3

Back to the equation:

-(6x+3)





We calculate terms in parentheses: -(12(x+1)-2), so:

12(x+1)-2

We multiply parentheses

12x+12-2

We add all the numbers together, and all the variables

12x+10

Back to the equation:

-(12x+10)



We add all the numbers together, and all the variables

-6x-(6x+3)-(12x+10)-11=0

We get rid of parentheses

-6x-6x-12x-3-10-11=0

We add all the numbers together, and all the variables

-24x-24=0

We move all terms containing x to the left, all other terms to the right

-24x=24

x=24/-24

x=-1

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