4(3x-5)=14x+12-20x=

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Solution for 4(3x-5)=14x+12-20x= equation: 



4(3x-5)=14x+12-20x=

We move all terms to the left:

4(3x-5)-(14x+12-20x)=0

We add all the numbers together, and all the variables

4(3x-5)-(-6x+12)=0

We multiply parentheses

12x-(-6x+12)-20=0

We get rid of parentheses

12x+6x-12-20=0

We add all the numbers together, and all the variables

18x-32=0

We move all terms containing x to the left, all other terms to the right

18x=32

x=32/18

x=1+7/9

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