7-(4m+3)=3(m+2)-(2m+3)

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Solution for 7-(4m+3)=3(m+2)-(2m+3) equation: 



7-(4m+3)=3(m+2)-(2m+3)

We move all terms to the left:

7-(4m+3)-(3(m+2)-(2m+3))=0

We get rid of parentheses

-4m-(3(m+2)-(2m+3))-3+7=0



We calculate terms in parentheses: -(3(m+2)-(2m+3)), so:

3(m+2)-(2m+3)

We multiply parentheses

3m-(2m+3)+6

We get rid of parentheses

3m-2m-3+6

We add all the numbers together, and all the variables

m+3

Back to the equation:

-(m+3)



We add all the numbers together, and all the variables

-4m-(m+3)+4=0

We get rid of parentheses

-4m-m-3+4=0

We add all the numbers together, and all the variables

-5m+1=0

We move all terms containing m to the left, all other terms to the right

-5m=-1

m=-1/-5

m=1/5

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