1/3(9x-12)+2x=41

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Solution for 1/3(9x-12)+2x=41 equation: 



1/3(9x-12)+2x=41

We move all terms to the left:

1/3(9x-12)+2x-(41)=0



Domain of the equation: 3(9x-12)!=0

x∈R



We add all the numbers together, and all the variables

2x+1/3(9x-12)-41=0

We multiply all the terms by the denominator


2x*3(9x-12)-41*3(9x-12)+1=0

Wy multiply elements

6x^2(9-123x(9+1=0

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