7+4x=(7x-2(x+5))+5

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Solution for 7+4x=(7x-2(x+5))+5 equation: 



7+4x=(7x-2(x+5))+5

We move all terms to the left:

7+4x-((7x-2(x+5))+5)=0



We calculate terms in parentheses: -((7x-2(x+5))+5), so:

(7x-2(x+5))+5



We calculate terms in parentheses: +(7x-2(x+5)), so:

7x-2(x+5)

We multiply parentheses

7x-2x-10

We add all the numbers together, and all the variables

5x-10

Back to the equation:

+(5x-10)



We get rid of parentheses

5x-10+5

We add all the numbers together, and all the variables

5x-5

Back to the equation:

-(5x-5)



We get rid of parentheses

4x-5x+5+7=0

We add all the numbers together, and all the variables

-1x+12=0

We move all terms containing x to the left, all other terms to the right

-x=-12

x=-12/-1

x=+12

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