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x/(x+1)+5(x-1)=1
We move all terms to the left:
x/(x+1)+5(x-1)-(1)=0
Domain of the equation: (x+1)!=0We multiply parentheses
We move all terms containing x to the left, all other terms to the right
x!=-1
x∈R
x/(x+1)+5x-5-1=0
We multiply all the terms by the denominator
x+5x*(x+1)-5*(x+1)-1*(x+1)=0
We multiply parentheses
5x^2+x+5x-5x-1*(x+1)-5=0
We add all the numbers together, and all the variables
5x^2+x-1*(x+1)-5=0
We move all terms containing x to the left, all other terms to the right
5x^2+x-1*(x+1)=5
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