7+3(6+2k)=6(k+3)+7

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Solution for 7+3(6+2k)=6(k+3)+7 equation: 



7+3(6+2k)=6(k+3)+7

We move all terms to the left:

7+3(6+2k)-(6(k+3)+7)=0

We add all the numbers together, and all the variables

3(2k+6)-(6(k+3)+7)+7=0

We multiply parentheses

6k-(6(k+3)+7)+18+7=0



We calculate terms in parentheses: -(6(k+3)+7), so:

6(k+3)+7

We multiply parentheses

6k+18+7

We add all the numbers together, and all the variables

6k+25

Back to the equation:

-(6k+25)



We add all the numbers together, and all the variables

6k-(6k+25)+25=0

We get rid of parentheses

6k-6k-25+25=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0

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