-3(a+1)=3(a-5)

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Solution for -3(a+1)=3(a-5) equation: 



-3(a+1)=3(a-5)

We move all terms to the left:

-3(a+1)-(3(a-5))=0

We multiply parentheses

-3a-(3(a-5))-3=0



We calculate terms in parentheses: -(3(a-5)), so:

3(a-5)

We multiply parentheses

3a-15

Back to the equation:

-(3a-15)



We get rid of parentheses

-3a-3a+15-3=0

We add all the numbers together, and all the variables

-6a+12=0

We move all terms containing a to the left, all other terms to the right

-6a=-12

a=-12/-6

a=+2

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