7+2(j-4)=2j+8

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Solution for 7+2(j-4)=2j+8 equation: 



7+2(j-4)=2j+8

We move all terms to the left:

7+2(j-4)-(2j+8)=0

We multiply parentheses

2j-(2j+8)-8+7=0

We get rid of parentheses

2j-2j-8-8+7=0

We add all the numbers together, and all the variables

-9!=0

There is no solution for this equation

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