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7+(5y-10)=(y+5)+y
We move all terms to the left:
7+(5y-10)-((y+5)+y)=0
We get rid of parentheses
5y-((y+5)+y)-10+7=0
We calculate terms in parentheses: -((y+5)+y), so:We add all the numbers together, and all the variables
(y+5)+y
We add all the numbers together, and all the variables
y+(y+5)
We get rid of parentheses
y+y+5
We add all the numbers together, and all the variables
2y+5
Back to the equation:
-(2y+5)
5y-(2y+5)-3=0
We get rid of parentheses
5y-2y-5-3=0
We add all the numbers together, and all the variables
3y-8=0
We move all terms containing y to the left, all other terms to the right
3y=8
y=8/3
y=2+2/3
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