2y+10(y-0.5)=2.5y-(0.5y+1)

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Solution for 2y+10(y-0.5)=2.5y-(0.5y+1) equation: 



2y+10(y-0.5)=2.5y-(0.5y+1)

We move all terms to the left:

2y+10(y-0.5)-(2.5y-(0.5y+1))=0

We multiply parentheses

2y+10y-(2.5y-(0.5y+1))-5=0



We calculate terms in parentheses: -(2.5y-(0.5y+1)), so:

2.5y-(0.5y+1)

We get rid of parentheses

2.5y-0.5y-1

We add all the numbers together, and all the variables

2y-1

Back to the equation:

-(2y-1)



We add all the numbers together, and all the variables

12y-(2y-1)-5=0

We get rid of parentheses

12y-2y+1-5=0

We add all the numbers together, and all the variables

10y-4=0

We move all terms containing y to the left, all other terms to the right

10y=4

y=4/10

y=2/5

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