7+(1/4x)=1/3x

Solution for 7+(1/4x)=1/3x equation:

7+(1/4x)=1/3x

We move all terms to the left:

7+(1/4x)-(1/3x)=0


Domain of the equation: 4x)!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/4x)-(+1/3x)+7=0

We get rid of parentheses

1/4x-1/3x+7=0

We calculate fractions


3x/12x^2+(-4x)/12x^2+7=0

We multiply all the terms by the denominator


3x+(-4x)+7*12x^2=0

Wy multiply elements

84x^2+3x+(-4x)=0

We get rid of parentheses

84x^2+3x-4x=0

We add all the numbers together, and all the variables

84x^2-1x=0

a = 84; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·84·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*84}=\frac{0}{168}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*84}=\frac{2}{168}
=1/84
$