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(3x-1)(6x+3)=0
We multiply parentheses ..
(+18x^2+9x-6x-3)=0
We get rid of parentheses
18x^2+9x-6x-3=0
We add all the numbers together, and all the variables
18x^2+3x-3=0
a = 18; b = 3; c = -3;
Δ = b2-4ac
Δ = 32-4·18·(-3)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-15}{2*18}=\frac{-18}{36} =-1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+15}{2*18}=\frac{12}{36} =1/3 $
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