7(z-4)-10=3z-2

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Solution for 7(z-4)-10=3z-2 equation: 



7(z-4)-10=3z-2

We move all terms to the left:

7(z-4)-10-(3z-2)=0

We multiply parentheses

7z-(3z-2)-28-10=0

We get rid of parentheses

7z-3z+2-28-10=0

We add all the numbers together, and all the variables

4z-36=0

We move all terms containing z to the left, all other terms to the right

4z=36

z=36/4

z=9

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