-3y-12=-10+4(y+10)

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Solution for -3y-12=-10+4(y+10) equation: 



-3y-12=-10+4(y+10)

We move all terms to the left:

-3y-12-(-10+4(y+10))=0



We calculate terms in parentheses: -(-10+4(y+10)), so:

-10+4(y+10)

determiningTheFunctionDomain
4(y+10)-10

We multiply parentheses

4y+40-10

We add all the numbers together, and all the variables

4y+30

Back to the equation:

-(4y+30)



We get rid of parentheses

-3y-4y-30-12=0

We add all the numbers together, and all the variables

-7y-42=0

We move all terms containing y to the left, all other terms to the right

-7y=42

y=42/-7

y=-6

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