7(z+4)=5(z+8)

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Solution for 7(z+4)=5(z+8) equation: 



7(z+4)=5(z+8)

We move all terms to the left:

7(z+4)-(5(z+8))=0

We multiply parentheses

7z-(5(z+8))+28=0



We calculate terms in parentheses: -(5(z+8)), so:

5(z+8)

We multiply parentheses

5z+40

Back to the equation:

-(5z+40)



We get rid of parentheses

7z-5z-40+28=0

We add all the numbers together, and all the variables

2z-12=0

We move all terms containing z to the left, all other terms to the right

2z=12

z=12/2

z=6

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