-4(2z-3)=7(z+8)

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Solution for -4(2z-3)=7(z+8) equation: 



-4(2z-3)=7(z+8)

We move all terms to the left:

-4(2z-3)-(7(z+8))=0

We multiply parentheses

-8z-(7(z+8))+12=0



We calculate terms in parentheses: -(7(z+8)), so:

7(z+8)

We multiply parentheses

7z+56

Back to the equation:

-(7z+56)



We get rid of parentheses

-8z-7z-56+12=0

We add all the numbers together, and all the variables

-15z-44=0

We move all terms containing z to the left, all other terms to the right

-15z=44

z=44/-15

z=-2+14/15

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