7(z+3)-4(z+2)=19

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Solution for 7(z+3)-4(z+2)=19 equation:


Simplifying
7(z + 3) + -4(z + 2) = 19

Reorder the terms:
7(3 + z) + -4(z + 2) = 19
(3 * 7 + z * 7) + -4(z + 2) = 19
(21 + 7z) + -4(z + 2) = 19

Reorder the terms:
21 + 7z + -4(2 + z) = 19
21 + 7z + (2 * -4 + z * -4) = 19
21 + 7z + (-8 + -4z) = 19

Reorder the terms:
21 + -8 + 7z + -4z = 19

Combine like terms: 21 + -8 = 13
13 + 7z + -4z = 19

Combine like terms: 7z + -4z = 3z
13 + 3z = 19

Solving
13 + 3z = 19

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-13' to each side of the equation.
13 + -13 + 3z = 19 + -13

Combine like terms: 13 + -13 = 0
0 + 3z = 19 + -13
3z = 19 + -13

Combine like terms: 19 + -13 = 6
3z = 6

Divide each side by '3'.
z = 2

Simplifying
z = 2

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