2(b+10)+5(b+1)=67

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Solution for 2(b+10)+5(b+1)=67 equation:


Simplifying
2(b + 10) + 5(b + 1) = 67

Reorder the terms:
2(10 + b) + 5(b + 1) = 67
(10 * 2 + b * 2) + 5(b + 1) = 67
(20 + 2b) + 5(b + 1) = 67

Reorder the terms:
20 + 2b + 5(1 + b) = 67
20 + 2b + (1 * 5 + b * 5) = 67
20 + 2b + (5 + 5b) = 67

Reorder the terms:
20 + 5 + 2b + 5b = 67

Combine like terms: 20 + 5 = 25
25 + 2b + 5b = 67

Combine like terms: 2b + 5b = 7b
25 + 7b = 67

Solving
25 + 7b = 67

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-25' to each side of the equation.
25 + -25 + 7b = 67 + -25

Combine like terms: 25 + -25 = 0
0 + 7b = 67 + -25
7b = 67 + -25

Combine like terms: 67 + -25 = 42
7b = 42

Divide each side by '7'.
b = 6

Simplifying
b = 6

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