7(y-4)=3(y-2)

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Solution for 7(y-4)=3(y-2) equation: 



7(y-4)=3(y-2)

We move all terms to the left:

7(y-4)-(3(y-2))=0

We multiply parentheses

7y-(3(y-2))-28=0



We calculate terms in parentheses: -(3(y-2)), so:

3(y-2)

We multiply parentheses

3y-6

Back to the equation:

-(3y-6)



We get rid of parentheses

7y-3y+6-28=0

We add all the numbers together, and all the variables

4y-22=0

We move all terms containing y to the left, all other terms to the right

4y=22

y=22/4

y=5+1/2

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