5(y+3)=2(y-4)

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Solution for 5(y+3)=2(y-4) equation: 



5(y+3)=2(y-4)

We move all terms to the left:

5(y+3)-(2(y-4))=0

We multiply parentheses

5y-(2(y-4))+15=0



We calculate terms in parentheses: -(2(y-4)), so:

2(y-4)

We multiply parentheses

2y-8

Back to the equation:

-(2y-8)



We get rid of parentheses

5y-2y+8+15=0

We add all the numbers together, and all the variables

3y+23=0

We move all terms containing y to the left, all other terms to the right

3y=-23

y=-23/3

y=-7+2/3

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