7(y-4)-3=-3(-9y+7)-4y

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Solution for 7(y-4)-3=-3(-9y+7)-4y equation: 



7(y-4)-3=-3(-9y+7)-4y

We move all terms to the left:

7(y-4)-3-(-3(-9y+7)-4y)=0

We multiply parentheses

7y-(-3(-9y+7)-4y)-28-3=0



We calculate terms in parentheses: -(-3(-9y+7)-4y), so:

-3(-9y+7)-4y

We add all the numbers together, and all the variables

-4y-3(-9y+7)

We multiply parentheses

-4y+27y-21

We add all the numbers together, and all the variables

23y-21

Back to the equation:

-(23y-21)



We add all the numbers together, and all the variables

7y-(23y-21)-31=0

We get rid of parentheses

7y-23y+21-31=0

We add all the numbers together, and all the variables

-16y-10=0

We move all terms containing y to the left, all other terms to the right

-16y=10

y=10/-16

y=-5/8

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