1/3(18-12x)=-(2x-7)+3

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Solution for 1/3(18-12x)=-(2x-7)+3 equation: 



1/3(18-12x)=-(2x-7)+3

We move all terms to the left:

1/3(18-12x)-(-(2x-7)+3)=0



Domain of the equation: 3(18-12x)!=0

x∈R



We add all the numbers together, and all the variables

1/3(-12x+18)-(-(2x-7)+3)=0

We multiply all the terms by the denominator


-((-(2x-7)+3))*3(-12x+18)+1=0



We calculate terms in parentheses: -((-(2x-7)+3))*3(-12x+18), so:

(-(2x-7)+3))*3(-12x+18

We add all the numbers together, and all the variables

-12x+(-(2x-7)+3))*3(+18

Back to the equation:

-(-12x+(-(2x-7)+3))*3(+18)



We add all the numbers together, and all the variables

-(-12x+(-(2x-7)+3))*318+1=0

We move all terms containing x to the left, all other terms to the right

-(-12x+(-(2x-7)+3))*318=-1

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