7(y-3)+y=4(6+2y)

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Solution for 7(y-3)+y=4(6+2y) equation: 



7(y-3)+y=4(6+2y)

We move all terms to the left:

7(y-3)+y-(4(6+2y))=0

We add all the numbers together, and all the variables

7(y-3)+y-(4(2y+6))=0

We add all the numbers together, and all the variables

y+7(y-3)-(4(2y+6))=0

We multiply parentheses

y+7y-(4(2y+6))-21=0



We calculate terms in parentheses: -(4(2y+6)), so:

4(2y+6)

We multiply parentheses

8y+24

Back to the equation:

-(8y+24)



We add all the numbers together, and all the variables

8y-(8y+24)-21=0

We get rid of parentheses

8y-8y-24-21=0

We add all the numbers together, and all the variables

-45!=0

There is no solution for this equation

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