20x2-x-12=0

Solution for 20x2-x-12=0 equation:

20x^2-x-12=0

We add all the numbers together, and all the variables

20x^2-1x-12=0

a = 20; b = -1; c = -12;
Δ = b2-4ac
Δ = -12-4·20·(-12)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{961}=31$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-31}{2*20}=\frac{-30}{40}
=-3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+31}{2*20}=\frac{32}{40}
=4/5
$