5(3x+9)-2x=15-2(x-5)=

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Solution for 5(3x+9)-2x=15-2(x-5)= equation: 



5(3x+9)-2x=15-2(x-5)=

We move all terms to the left:

5(3x+9)-2x-(15-2(x-5))=0

We add all the numbers together, and all the variables

-2x+5(3x+9)-(15-2(x-5))=0

We multiply parentheses

-2x+15x-(15-2(x-5))+45=0



We calculate terms in parentheses: -(15-2(x-5)), so:

15-2(x-5)

determiningTheFunctionDomain
-2(x-5)+15

We multiply parentheses

-2x+10+15

We add all the numbers together, and all the variables

-2x+25

Back to the equation:

-(-2x+25)



We add all the numbers together, and all the variables

13x-(-2x+25)+45=0

We get rid of parentheses

13x+2x-25+45=0

We add all the numbers together, and all the variables

15x+20=0

We move all terms containing x to the left, all other terms to the right

15x=-20

x=-20/15

x=-1+1/3

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