7(y-3)+5=6+2(y+4)

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Solution for 7(y-3)+5=6+2(y+4) equation: 



7(y-3)+5=6+2(y+4)

We move all terms to the left:

7(y-3)+5-(6+2(y+4))=0

We multiply parentheses

7y-(6+2(y+4))-21+5=0



We calculate terms in parentheses: -(6+2(y+4)), so:

6+2(y+4)

determiningTheFunctionDomain
2(y+4)+6

We multiply parentheses

2y+8+6

We add all the numbers together, and all the variables

2y+14

Back to the equation:

-(2y+14)



We add all the numbers together, and all the variables

7y-(2y+14)-16=0

We get rid of parentheses

7y-2y-14-16=0

We add all the numbers together, and all the variables

5y-30=0

We move all terms containing y to the left, all other terms to the right

5y=30

y=30/5

y=6

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