3(n+1)=3(n+1)+n

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Solution for 3(n+1)=3(n+1)+n equation: 



3(n+1)=3(n+1)+n

We move all terms to the left:

3(n+1)-(3(n+1)+n)=0

We multiply parentheses

3n-(3(n+1)+n)+3=0



We calculate terms in parentheses: -(3(n+1)+n), so:

3(n+1)+n

We add all the numbers together, and all the variables

n+3(n+1)

We multiply parentheses

n+3n+3

We add all the numbers together, and all the variables

4n+3

Back to the equation:

-(4n+3)



We get rid of parentheses

3n-4n-3+3=0

We add all the numbers together, and all the variables

-n=0

n=0/-1

n=0

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