7(y-1)=6y+5-3(-3y-2)

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Solution for 7(y-1)=6y+5-3(-3y-2) equation: 



7(y-1)=6y+5-3(-3y-2)

We move all terms to the left:

7(y-1)-(6y+5-3(-3y-2))=0

We multiply parentheses

7y-(6y+5-3(-3y-2))-7=0



We calculate terms in parentheses: -(6y+5-3(-3y-2)), so:

6y+5-3(-3y-2)

determiningTheFunctionDomain
6y-3(-3y-2)+5

We multiply parentheses

6y+9y+6+5

We add all the numbers together, and all the variables

15y+11

Back to the equation:

-(15y+11)



We get rid of parentheses

7y-15y-11-7=0

We add all the numbers together, and all the variables

-8y-18=0

We move all terms containing y to the left, all other terms to the right

-8y=18

y=18/-8

y=-2+1/4

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